Розрахунок: V1p2XU - 1
v =
| e^2 |
/ ( 4* π * ε0* n* ℏ) |
|
|
v =
$$v$$ = $$\frac{e^{2}}{4\cdot \pi\cdot \varepsilon0\cdot n\cdot \hbar}$$
| e^2 |
| / ( 4* π* ε0* n* ℏ) |
v =
$$v$$ = $$\frac{e^{2}}{4\cdot n\cdot \varepsilon0\cdot \pi\cdot \hbar}$$
| e^2 |
| / 4/ n/ ε0/ π/ ℏ |
v =
$$v$$ = $$\frac{0.25\cdot e^{2}}{n\cdot \varepsilon0\cdot \pi\cdot \hbar}$$
| 0.25* e^2 |
| / n/ ε0/ π/ ℏ |