Розрахунок: mGU6CS - 1
h* ν =
E_k-E_n
E_k-E_n
|
h* ν = E_k-E_n$$h\cdot \nu$$ = $$E_{k}-E_{n}$$
h =
$$h$$ = $$\frac{E_{k}-E_{n}}{\nu}$$
| (E_k-E_n) |
| / ν |
h =
-
$$h$$ = $$\frac{E_{k}}{\nu}-\frac{E_{n}}{\nu}$$
| E_k |
| / ν |
| E_n |
| / ν |