Розрахунок: 6bR1TK - 1
| sin(α) |
| / sin(γ) |
| n2 |
| / n1 |
|
| sin(α) |
| / sin(γ) |
| n2 |
| / n1 |
sin(α) =
$$sin(\alpha)$$ = $$\frac{n2\cdot sin(\gamma)}{n1}$$
| n2* sin(γ) |
| / n1 |
α = arcsin(
)$$\alpha$$ = $$arcsin(\frac{n2\cdot sin(\gamma)}{n1})$$
| n2* sin(γ) |
| / n1 |